Chapter 1
Class groups and units
1.1. Notation and background
Throughout, we will let be a number field. We recall a number of objects attached to and finite Galois extensions thereof and results regarding them.
Notation 1.1.1. §
To a number field, we attach the following objects:
- the ring of integers of ,
- the unit group of , which is to say the unit group of ,
- the ideal group of , i.e., the group of nonzero finitely generated -submodules of ,
- the prinicipal ideal group of , i.e., those -submodules of generated by a single element , and
- the class group of .
Remark 1.1.2. §
The class group is a finite abelian group.
These objects fit into the following nice commutative diagram
Diagram description: Units, principal ideals, ideals, and the class group
The structural squares and triangles displayed here commute. The lower row is exact; the map from the multiplicative group to ideals factors through the principal ideals in the upper row.
Objects, listed by row and column:
- Row 1, from left to right: column 6: P subscript (F).
- Row 2, from left to right: column 1: 1; column 3: script O subscript (F) superscript (times); column 5: F superscript (times); column 7: I subscript (F); column 9: Cl subscript (F); column 11: 0.
Arrows and lines:
- A hooked arrow from P subscript (F) to I subscript (F), without a label.
- An arrow from 1 to script O subscript (F) superscript (times), without a label.
- An arrow from script O subscript (F) superscript (times) to F superscript (times), without a label.
- An arrow from F superscript (times) to I subscript (F), without a label.
- A double-headed arrow from F superscript (times) to P subscript (F), without a label.
- An arrow from I subscript (F) to Cl subscript (F), without a label.
- An arrow from Cl subscript (F) to 0, without a label.
in which the lower row is exact.
Definition 1.1.3. §
The absolute norm of a nonzero ideal of is the index .
Notation 1.1.4. §
The number of real places of is denoted , and the number of complex places of is denoted .
Remark 1.1.5. §
Since each complex places consists of a pair of complex conjugate embeddings of , the degree formula tells us that .
Theorem 1.1.6 (Dirichlet’s unit theorem). §
The unit group is a finitely generated abelian group of rank with torsion subgroup the group of roots of unity in .
Next, we turn quickly to the zeta function of a number field.
Definition 1.1.7. §
The Dedekind -series of a number field is
for with real part , where the sum is taken over nonzero ideals of .
Theorem 1.1.8. §
The Dedekind -series of converges absolutely on with . It has a unique mermomorphic continuation to which is holomorphic outside and has a simple pole at .
With this in hand, we define the Dedekind zeta function to be the meromorphic continuation of to .
Definition 1.1.9. §
The Dedekind zeta function of a number field is the meromorphic continuation to of the Dedekind -series .
The Dedekind zeta function has the following functional equation relating its values at and .
Theorem 1.1.10. §
Let
where is the gamma function and denotes the discriminant of . Then is analytic on and satisfies
For any Galois extension and prime of , let denote a Frobenius at a prime over . We have
for . If is unramified, its conjugacy class in depends only on , and let us denote it by . If is abelian and unramified, we denote the unique Frobenius more simply by .
Theorem 1.1.11 (Čebotarev density theorem). §
Let be a finite Galois extension of number fields with group . Let be the set of unramified primes in . Let be a conjugacy class in . Then
We will denote the class of a fractional ideal by . The class group has an other description in terms of the Hilbert class field of , which is to say the maximal unramified abelian extension of . We recall the following classical result of class field theory.
Theorem 1.1.12. §
The Artin map
defined by for all primes of , is an isomorphism.
1.2. Regulators
Let be a number field. We will shorten our notation for units slightly as follows.
Notation 1.2.1. §
We set .
Definition 1.2.2. §
We say that a set of units of is independent if it generates a subgroup of isomorphic to .
We will use the following notation.
Notation 1.2.3. §
Set . Let be the real embeddings of and be representatives of the distinct complex conjugacy classes of complex embeddings of . Let and
We define an -linear homomorphism by
where
The following is typically proven in the course of a proof of Dirichlet’s unit theorem. Let denote the restriction of to a map , the image landing in by the product formula.
Proposition 1.2.4. §
The map is an isomorphism.
Definition 1.2.5. §
The regulator of a set of independent units is , where is the -by- matrix with -entry .
Remark 1.2.6. §
Exactly one archimedean place is omitted in the definition of the regulator. For any , one has
by the product formula, so the rows of the matrix determining the regulator sum to the what would have been the row corresponding to the embedding that is omitted. The choice of and their ordering are then seen by the usual rules for the effect of row operations on determinants to not affect the absolute value of the determinant of the matrix in question.
In particular, we have the following.
Lemma 1.2.7. §
For a set of independent units, is the absolute value of the determinant of the linear transformation relative to the basis of given by the and the basis of given by for .
Definition 1.2.8. §
Let and be subgroups of an abelian group.
- a.
-
We say that and are commensurable if and are of finite index in .
- b.
-
If and are commensurable, then we define the relative index of in by
The following is easily verified.
Lemma 1.2.9. §
Let and be finitely generated subgroups of a vector space over a subfield of . If and are commensurable, then there exists an -linear automorphism of such that , and for any such , we have .
Lemma 1.2.10. §
Suppose that and are independent sets of units in , where . Let
Then
Proof.
Let . There exists an automorphism of carrying the image of in to the image of . Since both and contain , we have . On the other hand, is an -linear isomorphism, so
with the determinant taken relative to the bases of Lemma 1.2.7. □
Corollary 1.2.11. §
If and are independent sets in with images generating the same subgroup of , then
We may then make the following definitions.
Definition 1.2.12. §
A fundamental set of units of a number field is a set of units in such that
Definition 1.2.13. §
The regulator of a number field is for any fundamental set of units of .
We also need the following notation.
Notation 1.2.14. §
Let denote the number of roots of unity in a number field .
Now that we have defined the regulator, we can describe the residue at of the Dedekind zeta function.
Theorem 1.2.15 (Analytic class number formula). §
For a number field , one has
1.3. Finite Galois extensions
Suppose that is a finite Galois extension, and let . Then becomes a -module via the action for and , where
The Galois group is a -module too, but to see this requires a little bit of work.
Proposition 1.3.1. §
Let be a finite Galois extension of . Then is Galois.
Proof.
Let denote the Galois closure of as an extension of . Let . For , let denote a lift of to . Note that the field is independent of the choice of lift of , as any element in necessarily preserves the subfield of , as is Galois.
Next, we claim that
It suffices to show that is Galois by the minimality of as a Galois extension of . For this, note that for any , one has
where , by the independence of conjugates of from the choice of lift. This proves the claim. It then follows that is abelian, since each is. That is, any has the property that , and the latter group is abelian.
Now, let be the inertia group at a prime of in the abelian extension . If is nontrivial, then its image in some must be as well. Then has nontrivial image in . Since the former group equals the inertia group and is unramified, this image must be trivial. Therefore , and so is an unramified abelian extension of containing . By the maximality of , we have , as desired. □
Consequently, if is finite Galois with group , then becomes a -module for the conjugation action: acts on by sending it to . The following is then a consequence of class field theory.
Proposition 1.3.2. §
For finite Galois with Galois group , then Artin map is -equivariant (i.e., a -module homomorphism), which is to say that
for all and .
Definition 1.3.3. §
For finite Galois, we define a map
and the norm map
Our goal in this section will be to study these maps.
Lemma 1.3.4. §
Let be a prime, and let denote the -part of the class group of any number field . If the order of is prime to , then the maps
defined by and , respectively, are isomorphisms.
Proof.
Note that , so is injective on and the image of contains . Let , and note that is a -module. Define an idempotent
Since , the group is both a submodule and a quotient of . Note that , which forces to have image on . The map induced by is therefore an isomorphism. As is finite, both and have the same order, so therefore now the same order as . Since induces a surjective map , that map must also be an isomorphism. □
For instance, we have that for any prime , as is prime to .
Proposition 1.3.5. §
Let be a finite Galois extension of number fields with Galois group . There is a canonical exact sequence
Proof.
By Hilbert’s Theorem 90, we have a commutative diagram
Diagram description: Hilbert theorem 90 and invariant principal idealsThe two displayed rows are exact, and the squares commute. Objects, listed by row and column:
Arrows and lines:
|
and it provides an isomorphism . Noting this and applying the snake lemma to the commutative diagram
Diagram description: Invariant ideals and class groupsThe two displayed rows are exact, and the squares commute. Objects, listed by row and column:
Arrows and lines:
|
we obtain the desired exact sequence. □
Note that the map is given explicitly by taking to a cocycle , where satisfies . The map is given by taking a cocycle to the image of an element with for all .
Definition 1.3.6. §
An ideal in with class in the kernel of is said to capitulate in the extension . The kernel of is known as the capitulation kernel.
Lemma 1.3.7. §
Let be a Galois extension of number fields with Galois group . The cokernel of is canonically isomorphic to the Galois group of the maximal unramified abelian subextension of inside .
Proof.
The norm map on ideal classes factors the the -coinvariant group of . We consider the complex
Using the Artin map, we may write the latter complex as
where the first map is restriction, and therefore has image . It follows that
as desired. □
Lemma 1.3.7 has the following immediate corollary.
Corollary 1.3.8. §
If is totally ramified at any prime, then is surjective.
Now suppose that is abelian. Let denote the inertia group in at a prime of , and let
denote the map that is the product of the natural inclusions.
Proposition 1.3.9. §
Let be an abelian extension of number fields with Galois group . Then there is an exact sequence
where is the quotient of by its subgroup that is taken to the commutator subgroup of under the Artin map.
Proof.
The exactness outside of follows from Lemma 1.3.7, since by definiton.
We define
as follows. Employing the Artin map, we have canonical isomorphisms
where is the maximal unramified extension of that is abelian over . Let denote the inertia group at a prime over in . As is unramified, maps isomorphically to under restriction. We have a map
given by the product of the canonial inclusions, and the map from is then given by the identifications . Since lands in under this map, we have the desired map.
It remains to check exactness at . Again, we use the Artin isomorphism to see that the kernel of the map to is precisely . On the other hand, the image of in is the intersection with of the subgroup of generated by its inertia groups. As is abelian and is the Hilbert class field of , this is precisely . □
We have the following interesting corollary.
Corollary 1.3.10. §
Let be a cyclic -extension, and suppose that there is at most one prime of that ramifies in it. Then the map induced by is injective.
Proof.
Since is cyclic, the quotient of Proposition 1.3.9 equals . Since is either at the unique ramified prime, or if there is no ramified prime, the map is injective. □
In the case that divides the order of , we can give another nice consequence. First, we require the following lemma.
Lemma 1.3.11. §
Suppose that is a finite Galois -extension ramified at no more than one prime of . If is nonabelian, suppose further that, if there is such a prime, that it is nonsplit in the extension. Then if , we have as well.
Proof.
We begin with the case that is abelian. By Corollary 1.3.10, the map is injective, and therefore . Thus, we have
Noting Proposition 2.3.7, Nakayama’s lemma then tells us that .
Since any finite -group has a finite filtration with abelian (or even cyclic) graded quotients, the result in general follows from the abelian case by recursion, noting that by assumption there is at most one prime that ramifies in each intermediate extension. □
We illustrate the use of this with the following interesting example.
Example 1.3.12. §
Let and . Then this extension is totally ramified of degree at the unique prime above in , which is for a primitive th root of unity . Therefore, we have that via the norm map. For a prime such that , which is known as a regular prime (e.g., all primes less than ), Lemma 1.3.11 implies that . When , it turns out that , and in fact we have that is isomorphic to as well.
To go even further, it is useful to restrict to the case of a cyclic extension. We begin with the following useful result.
Proposition 1.3.13. §
Let be a cyclic extension of number fields. Then
where runs over all primes of and is some prime of above .
Proof.
Let denote the decomposition group in at any over . Choose a set of representatives of . For , we have
so every global norm is a local norm everywhere.
Recall the following exact sequence for the Brauer group of :
where denotes the decomposition group in at any over . By the periodicity of Tate cohomology of a cyclic group, this becomes
In particular, we have an injection
Therefore, if is a local norm everywhere, it is a global norm, as desired. □
Note that an element is automatically a local norm at any prime where is unramified and the valuation of at that prime is trivial. Hence, there are actually only finitely many places to check that is a local norm to see that it is a global one.
We now derive a nine-term exact sequence that gives us information on the behavior of class groups in cyclic extensions. A proof is possible by making use of Tate cohomology, as found in the appendix to [HS], but we give a more explicit proof.
Theorem 1.3.14. §
Let be a cyclic extension of number fields, and let be its Galois group. Let denote the inertia group in at a prime of , and let
denote the map that is the product of the natural inclusions. Then we have an exact sequence
Moreover, the group is noncanonically isomorphic to .
Proof.
By Proposition 1.3.5, we have an exact sequence
including the first row. By Proposition 1.3.9, the final part of the sequence beginning with is exact.
Let be a generator of . Define
as the map that takes image of an ideal class to the image of , where is any generator of . To see that this is well-defined, note that if is replaced by another generator , then with , and
Moreover, if is replaced by an ideal with the same class, then for some . We then have
It follows that
Finally, if , then , so takes to .
We check exactness at . If , then again , so maps to . On the other hand, if takes the image of to , and therefore with . We then have
which means . As , we have that the image of is in the image of the map from .
Next, we define
by the direct sum of the local reciprocity maps . (We remark that for all but finitely many , so the map makes sense.) Since the product of the reciprocity maps at all places on a global element is trivial, the image of this map is indeed contained in Also, the map is well-defined since every global norm is a local norm. Note that the image of is the set of with . Again, such elements are local norms, and map to zero under each . Conversely, if satisfies for every , then for all , since is a unit. By Theorem 1.3.13, we have that for some with for some and . In other words, is the image of the image of the class of under .
We check exactness at . Let denote the maximal abelian extension of that is abelian over . For , we have
with lying over . Since , the image of in is , and the resulting product in is trivial. On the other hand, suppose that lifts some and
Then there exist local units for each with . We take if . By global class field theory, the idele with for each is the product of the norm of an idele of with an element . Recall that
so we have that
where we take if is archimedean. Since contains , the idele may be taken to be a unit at all places. But, as each is a local unit at all and
for all , this means that must be a unit at all places as well. That is, . As is a local norm from everywhere, we have
for every , as desired.
Finally, recall that is the free abelian group generated by the prime ideals of . For an element of to be fixed under , every prime in its decomposition must appear with the same exponent as its conjugates. That is, is generated by the , where are the primes of lying over a prime of . Of course, , where is the ramification index of the place corresponding to , so we have
□
Remark 1.3.15. §
Every map but the map between the two rows is canonical in the exact sequence of Theorem 1.3.14. The remaining map depends only upon a choice of generator of . It can be made canonical by considering instead the map
given on the image of a tensor of and by writing and taking the image of in the quotient.
Next, we generalize the situation slightly.
Notation 1.3.16. §
For a set of places in a number field , we let denote its subset of finite places and its subset of infinite places.
Definition 1.3.17. §
Let denote a set of places of .
- a.
-
The -class group of is the quotient of the class group by the subgroup generated by the classes of the finite primes in .
- b.
-
The Hilbert -class field of is the maximal unramified abelian extension of in which all primes in split completely.
- c.
-
The ring of -integers of is
where is used to denote a finite prime of and its additive valuation.
- d.
-
The -ideal group is the group of nonzero fractional ideals in , and the -principal ideal group is the subgroup of principal fractional ideals.
- e.
-
The -unit group in is .
Notation 1.3.18. §
If is a set of primes of and let is a finite extension, then we let denote the set of places of lying over those in . For brevity, we denote , , and so on more succinctly by , , and so on similarly. That is, we use in the subscript to denote . If is algebraic, we may still speak of its -integers as the union of -integers in the finite subextensions of in .
Let us fix a set of places of for the rest of this section.
Remark 1.3.19. §
The Artin isomorphism induces an isomorphism
We have an analogue of the exact sequence of Theorem 1.3.14 for -class groups and -units. The proof is much as before, and is therefore omitted.
Theorem 1.3.20. §
Let be a cyclic extension of number fields, and let be its Galois group. Let (resp., ) denote the inertia group (resp., decomposition group) in at a prime of , and let
denote the map that is the product of the natural inclusions. Then we have an exact sequence
1.4. Kummer theory
For a set of primes of , we let denote the set of finite places of in , we let denote the set of archimedean places, and for any , we let denote the set of primes of above for any prime dividing . If is an extension of , we generally also use the symbol to denote the set of primes of above those in . We will let denote the set of all primes of , so we may speak of and so forth. For brevity, let us set .
Definition 1.4.1. §
We say that an extension of is -ramified if it is unramified outside of the places in .
Lemma 1.4.2. §
There exists a maximal -ramified extension of , and it is Galois over .
Proof.
A union of -ramified extensions is -ramified, so the existence of is clear. If is an -ramified finite degree extension of , then so is any conjugate of over in an algebraic closure of containing , as the inertia degrees at conjugate primes above in and are the same (and similarly for real places). The product
is Galois (in fact, it is the Galois closure of in ) and also -ramified as a compositum of -ramified extensions. Therefore, is a union of finite Galois subextensions, hence itself Galois. □
Definition 1.4.3. §
We use to denote the Galois group , i.e., the Galois group of the maximal -ramified extension of .
Kummer theory in -ramified extensions has as its basis the following proposition.
Proposition 1.4.4. §
Let be a set of primes of . We have a canonical isomorphism
given by taking an ideal class to the cocycle that takes to , where is a generator of .
Proof.
To reduce clutter in the notation, let us set and . A similar argument to that of the proof of Proposition 1.3.5 produces an isomorphism
that takes to . Again similarly to before, we have the commutative diagram
Diagram description: S-ideals in an infinite extensionThe two displayed rows are exact, and the squares commute. Objects, listed by row and column:
Arrows and lines:
| (1.4.1) |
The lower row arises as a direct limit of like sequences for intermediate finite extensions of in . However, since contains the finite primes that are ramified in any such extension , the map is not merely an injection, but an isomorphism. Moreover, is the zero map, since contains by definition, and every ideal in becomes principal in . Hence, the snake lemma provides an isomorphism
taking to where . □
Proposition 1.4.5. §
Suppose that contains . Then there is a canonical exact sequence
Proof.
For any , the extension is unramified outside of and therefore trivial, as the only primes that can ramify in such a Kummer extension are the real places, those with , and those primes dividing , all of which are contained in . We then have that
is exact, and the result follows immediately from the exact sequence
□
In the case that , we have the following.
Lemma 1.4.6. §
Fix such that contains , and let be the subgroup
There is a canonical exact sequence
Proof.
From the short exact sequence
we obtain an exact sequence
| (1.4.2) |
As the th power map takes values in , the kernel of the rightmost map in (1.4.2) is contained in the kernel of
which is isomorphic to by Proposition 1.4.4. Noting that
equation (1.4.2) yields the result. □
Definition 1.4.7. §
A number field is said to be abelian if it is an abelian extension of .
Definition 1.4.8. §
A number field is said to be totally real if it has no complex places.
Remark 1.4.9. §
There exits a maximal totally real subfield of any number field , as the compositum of any two totally real fields is totally real.
Definition 1.4.10. §
A number field is CM if it has no real places and is a degree extension of .
Example 1.4.11. §
Let . Then the cyclotomic field is CM, and
where is a primitive th root of unity. As a consequence of this and the Kronecker-Weber theorem, every abelian field is either totally real or CM.
Fix a CM field , and let be the nontrivial element of . Given a -module , we have submodules
Note that
and is -torsion. If multiplication by is invertible on , then
Lemma 1.4.12. §
The groups and have the same -rank, and is the group of roots of unity in .
Proof.
The first statement is an immediate consequence of Dirichlet’s unit theorem. Since it holds, consists only of elements of finite order, which is to say, roots of unity. Since every root of unity satisfies , we have the result. □
We note that for an odd prime , the map provides a canonical identification of with by Lemma 1.3.4.
Lemma 1.4.13. §
The map induced by has kernel of order dividing .
Proof.
Note that if for , then must be a root of unity. On the other hand, the group of with contains . Thus is isomorphic to a quotient of . The result then follows from Proposition 1.3.5. □
Remark 1.4.14. §
If and are Galois extensions of a field with contained in , then acts on for any -module . The action is induced by the following action of on a cochain :
On cohomology, this action factors through an action on since, on , this action is the conjugation action on cohomology, which is trivial.
For a finitely generated abelian group , let us use to denote its rank and
to denote its -rank for a prime .
Theorem 1.4.15. §
Let be a CM field such that for an odd prime . We then have
where if is ramified at and otherwise.
Proof.
Note that
and
as acts on by inversion. Combining this with Lemma 1.4.6, with as in said lemma, we have
By Lemma 1.4.12, we have that and
while
The result follows. □
1.5. Leopoldt’s conjecture
For each place of , Let
and consider its subgroup
If is finite, then , and is the group of -power roots of unity in if does not lie over while is the group of -units if lies over . If is infinite, then , and both groups are trivial unless is real and , in which case they are .
Let us set
We may consider the natural map
Clearly, the kernel of is trivial for . Yet, the problem may arise that there exist, for instance, two units generating a rank two subgroup and such that . So, in theory, could have a kernel. This brings us to Leopoldt’s conjecture.
Conjecture 1.5.1 (Leopoldt). §
The map is injective.
Remark 1.5.2. §
We could, equivalently, consider the map
that includes the archimdean places, setting for such . The point is that for archimedean unless and is real, in which case .
We have that by definition. On the other hand, we have . In particular, the two kernels have the same -rank. Moreover, the -torsion in is , and is not in the kernel of for any , so if and only if .
Example 1.5.3. §
For , Leopoldt’s conjecture holds as for and for .
Let denote a finite set of primes of containing . We wish to state several equivalent forms of this conjecture. For this, we set
and extend to a map
Let denote the Galois group of the maximal abelian pro- unramified outside extension of . Let denote the Galois group of the maximal abelian pro- extension of for each . The following exact sequences will be useful.
Theorem 1.5.4. §
There are two exact sequences fitting into a commutative diagram
Diagram description: Two global reciprocity exact sequencesThe two displayed rows are exact, and the squares commute. Objects, listed by row and column:
Arrows and lines:
| (1.5.1) |
where is the product over of the composition of the -completion of the local reciprocity map with the natural map from onto the decomposition group at in , and where the maps are the natural quotient maps (under the indentifications given by the Artin map).
Proof.
In the horizontal sequences in the diagram (1.5.1), we note that (resp., the corresponding map in the upper sequence) is the compositum of the decomposition groups (resp., inertia groups) at all in . Being that already has trivial inertia groups at , the quotient is therefore the Galois group of the maximal unramified abelian -extension of in which all primes in split completely (resp., maximal unramified abelian -extension of ), and is therefore canonically isomorphic to (resp., ) via Artin reciprocity.
For the upper horizontal sequence, the exactness at will follow from the exactness at in the lower horizontal sequence by noting that consists exactly of the elements of that have image under lying in . We are therefore reduced to proving the latter exactness.
Recall that is identified via Kummer theory with the quotient , where is the subgroup of such that for some fractional ideal of . In other words, we have an exact sequence
It then follows from the finiteness of that
We claim that there is an exact sequence
where the first map is induced by the localization maps and the second map is taken modulo . In that all of the terms of this sequence are finite, we can take the inverse limit as we vary to obtain an exact sequence
| (1.5.2) |
finishing the verification of the exactness of the lower sequence.
Let us use and to denote the modulo reductions of and for any . Any has valuation a multiple of at , so lies in the compositum of the inertia group and the subgroup of th powers in . In particular, we have that for such . Global class field theory then tells us that
which tells us that (1.5.2) is a complex.
Let be the maximal -ramified abelian extension of of exponent . Its Galois group is the quotient of by the composition of all inertia groups at primes and the th powers of all of the decomposition groups. By global class field theory, we therefore have an isomorphism
where for simplicity of notation, we have set . Similarly, if we let be the maximal unramified abelian extension of of exponent in which every prime in splits completely, so that , class field theory again provides an isomorphism
We see, then, that we have isomorphisms
where in the first step, we have used the second isomorphism theorem. Since
and
we have an exact sequence
where the maps agree with the maps in question, hence the result. □
Remark 1.5.5. §
Theorem 1.5.4 can also be derived using Poitou-Tate duality and Kummer theory.
Proposition 1.5.6. §
The kernel of is contained in . In particular, Leopoldt’s conjecture is equivalent to the injectivity of .
Proof.
Let . Then may be written as
were and for each , for some . For each , we then have
which means that the are -linearly dependent if some . If , without loss of generality, then may be written as a sum of tensors. Continuing in this way, we obtain that some nonzero integer power of is a -linear combination of units at . Since there are only finitely many , we have for some , which forces . □
The following theorem is also a corollary of Theorem 1.5.4 and Proposition 1.5.6, which gives in particular equivalent conditions for Leopoldt’s conjecture to hold (noting that is -torsion free). Let denote the -rank of a finitely generated -module .
Theorem 1.5.7. §
The following are equivalent for a given :
- i.
-
,
- ii.
-
,
- iii.
-
, and
- iv.
-
.
Proof.
For , we have that
We also have
by Dirichlet’s unit theorem, and is finite. Note that
Hence, Proposition 1.5.6 and the exactness of the upper exact sequence in (1.5.1) yield the result. □
Corollary 1.5.8. §
The -module is finitely generated of -rank independent of containing .
The in Theorem 1.5.7 is known as the Leopoldt defect of
Definition 1.5.9. §
The Leopoldt defect is the -rank of .
Leopoldt’s conjecture for is equivalent to the statement that the Leopoldt defect is 0. We may also phrase Leopoldt’s conjecture for in terms of the nonvanishing of a -adic regulator of , which replaces the always nonzero complex regulator.
Definition 1.5.10. §
For a -adic field , the -adic logarithm of is the unique homomorphism such that and such that for any in the maximal ideal of , one has
Remark 1.5.11. §
The kernel of on a -adic field is .
Notation 1.5.12. §
We use to denote the completion of the algebraic closure of with respect to the unique extension of the -adic absolute value on . We have a -adic absolute value
with .
Remark 1.5.13. §
The -adic logarithm extends to a continuous homomorphism .
It turns out that and are abstractly isomorphic (being algebraically closed of characteristic and having the same cardinality), and we can fix an embedding . Let , and let for be the compositions of the real and complex embeddings of previously chosen in Section 1.2.
Definition 1.5.14. §
Let be independent units in . The -adic regulator of is the determinant of the -by- matrix , where is if is real and if is complex.
Remark 1.5.15. §
The -adic regulator is well-defined up to sign, so as an element of .
The following is immediate.
Proposition 1.5.16. §
Leopoldt’s conjecture for a number field is equivalent to the statement the nonvanishing of the -adic regulator .
Baker proved that if are such that are -linearly independent, then they are -linearly independent. Via Baker’s method, Brumer proved a -adic analogue.
Theorem 1.5.17 (Brumer). §
Let be algebraic numbers that are also -adic units, and suppose that the -adic logarithms are -linearly independent. Then these logarithms are also -linearly independent.
Using this result, Brumer was able to prove Leopoldt’s conjecture for an abelian extensions of number fields with . Note that the only fields with are and the imaginary quadratic fields. We need several preliminary results. We begin with the following result, only the first part of which is needed at the moment.
Proposition 1.5.18. §
Let be a finite abelian group and be a function. Let denote the group of characters .
- a.
-
We have
In fact, the rank of is the number of such that .
- b.
-
We have
Proof.
We compare two bases of the complex vector space of functions : the set of characters and the set of -functions
for . Consider the linear transformation given by
Applied to , we obtain
so is an eigenvector with eigenvalue . It follows that is the product of the latter sums over all . On the other hand,
so
so the -entry of the matrix of with respect to this basis is . In that the determinant and rank of are independent of the choice of basis, we have part a.
For part b, we consider the codimension subspace of that consisting of the with . One basis of these functions is given by , and another is given by the functions for . Also, we see immediately that . The determinant of with respect to the character basis is clearly the left-hand side of the desired equality. On the other hand, noting that
we have
which has the desired coefficients. □
We omit a proof of the following.
Lemma 1.5.19. §
For a field and a finite group , let and be -modules of finite -dimension. Suppose that there is a field extension of such that as -modules. Then as -modules.
Proposition 1.5.20. §
Let be an abelian extension with Galois group of either or an imaginary quadratic field. Then as -modules.
Proof.
By Proposition 1.2.4, we have , where is as in Notation 1.2.3. That is is a hyperplane in the -span of the archimedean places of , in this case consisting of the formal sums with coefficients summing to zero (since is either totally real or purely imaginary). Since has just one archimedean place, all of the places of are conjugate under the action determined by precomposition of a representative by the inverse of an element of . Fixing an embedding then provides an isomorphism , so . By Lemma 1.5.19, we then have that . □
Theorem 1.5.21 (Brumer). §
Leopoldt’s conjecture holds for all finite abelian extensions of and all finite abelian extensions of any imaginary quadratic field.
Proof.
By Proposition 1.5.20, we may pick be such that is an independent set of units of . Let , and consider the function defined by . Since
we have
If for some nontrivial character , then
Since . By Theorem 1.5.17, we then have that the quantities for are -linearly dependent, and hence -linearly dependent. That is, there exist elements , not all zero, such that
This, however, contradicts our choice of .
Now choose an ordering of and form the matrix , the -entry of which is . It then follows from Proposition 1.5.18a that this matrix has rank , and the row and column are linearly dependent on the others. If we remove them, the resulting -by- minor is the -adic regulator matrix attached to the basis with and the embeddings for . Thus , so Leopoldt’s conjecture holds for . □