Week 4 Discussion Notes

Table of Contents

Differentiation

If r(t)\vec{r}\p{t} is a curve, then the tangent vector to r\vec{r} at t=at = a is r(a)\vec{r}'\p{a}. On the other hand, the tangent line is the line that passes through r(a)\vec{r}\p{a} and has direction vector r(a)\vec{r}'\p{a}, i.e.,

L(t)=r(a)+tr(a)\vec{L}\p{t} = \vec{r}\p{a} + t\vec{r}'\p{a}

is a parametrization of the tangent line.

Arc Length

Here's a quick mnemonic to remember the arc-length formula:

From 1D, you should recall that Δff(x)Δx\Delta f \approx f'\p{x} \,\Delta{x}. This is just a different way to say that the tangent line to ff is the best linear approximation to ff. With vector-valued functions instead, we end up with

Δrr(t)Δt.\Delta\vec{r} \approx \vec{r}'\p{t} \,\Delta{t}.

If we take lengths and write ss for the arc-length function of r\vec{r}, then

Δsr(t)Δt.\Delta{s} \approx \norm{\vec{r}'\p{t}} \,\Delta{t}.

So, in the limit, we end up with

ds=r(t)dt    s=r(t)dt.\diff{s} = \norm{\vec{r}'\p{t}} \,\diff{t} \implies s = \int \norm{\vec{r}'\p{t}} \,\diff{t}.

From here, to actually use the formula, you'll also need to plug in the bounds for the integral.