Let be a field of characteristic . For an element , show that the polynomial is irreducible over if and only if it has no root in . Show also that, if is irreducible, then any root of it generates a cyclic extension of of degree .
Notice that over the splitting field of , if is a root of , then for , we have
For the third equality, we used the fact that , i.e., . Thus, if has a root in , then it automatically has all its roots in as well, so is irreducible if and only if has no roots in .
For the second claim, note that the calculation above shows that the splitting field of is where is any root of . Moreover, it also shows is separable, so is Galois. Hence, , so , which was what we wanted to show.