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1. Ultrafilters

A filter is the same thing as a dual ideal in the lattice of all subsets of a set--a power-set Boolean lattice. An ultrafilter is a maximal dual ideal in such a lattice.

Recall that in a Boolean algebra, choosing one prime ideal gets us a little burst of terminology: the prime ideal is also a maximal ideal, and its complement is a maximal dual ideal (an ultrafilter, if in a power-set lattice).

Now let $ I = \omega = \{0,1,2,\ldots\}$ and let $ B =$   Pow$ (I)$. Recall that there are two kinds of prime ideals in $ B$:

We shall often treat $ I$ as an index set.

Choose a prime ideal in Pow$ (I)$ and keep it fixed for the rest of this discussion. We think of its members as ``small'' sets of indices. What is a ``large'' set of indices? There are two possible definitions:

(1) A large set of indices is a set of indices that is not small--a member of the corresponding ultrafilter;

(2) a large set of indices is the complement in $ I$ of a small set of indices.

But these two definitions are equivalent! Recall that for a prime ideal in a Boolean lattice, for each $ x$ exactly one of $ x$ or $ x'$ is in the ideal.



Question. For the principal prime ideal generated by $ I \setminus \{k\}$, which subsets of $ I$ are small and which large? (It is as if only $ k$ counts for largeness.)



To summarize, if we have chosen a prime ideal, then with respect to it,

  1. Every subset of $ I$ is either large or small (not both).
  2. The complement in $ I$ of a large set is small and vice-versa.
  3. The small sets form our chosen prime ideal, by definition. In particular,
  4. If the prime ideal is nonprincipal, then any finite subset of $ I$ is small.
  5. The large sets form an ultrafilter. In particular,




next up previous
Next: dd_jonsson Up: dd_jonsson Previous: dd_jonsson
Kirby A. Baker 2003-03-26