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4. The first isomorphism theorem

For groups, recall the ``first isomorphism theorem'': If $ \varphi: G \rightarrow H$, then im$ \;\varphi \cong G/$ker$ \varphi$. Or equivalently, if $ \varphi: G \rightarrow H$ is a surjection with kernel $ K$, then $ H \cong G/K$.

This theorem is useful in examples. It also shows that the homomorphic images of a group $ G$ are determined up to isomorphism by information internal to $ G$. In particular, if $ G$ is finite then up to isomorphism $ G$ has only finitely many homomorphic images.



For algebras in general, the situation is the same:

4.1 Theorem (first isomorphism theorem). Let $ \varphi: {\cal A} \rightarrow {\cal B}$ be a homomorphism. Then im$ \;
\varphi \cong A/$ker$ \; \varphi$. Equivalently, if $ \varphi: {\cal A} \rightarrow {\cal B}$ is a surjective homomorphism with kernel $ \theta$, then $ {\cal B} \cong {\cal A}/\theta$.



4.2 Corollary. The possible homomorphic images of $ {\cal A}$ are determined up to isomorphism by the internal structure of $ {\cal A}$.





Kirby A. Baker 2003-02-18