Theorem. If
is well partially ordered, then so is
,
the set of finite words (finite sequences) from
, where
means that
,
, ...,
for some
.
Note that Example (c) above is the case where
is totally unordered.
Some useful notation: Let us write
for elements of
and
for elements of
.
The empty sequence is allowed. Let
mean
, let
mean
, etc. Observe that
is an upset of
and
is a downset. Also observe that for
,
is the same thing as
(where
is regarded as a one-letter word).
Proof of the Theorem.
Suppose
is not wpo. Let
be a downset of
minimal with respect to the property that
is not
wpo; by Observation 5, such a
exists. Without loss of
generality,
is
. Then for all
,
, or equivalently
,
is wpo. In contrast,
is
not wpo for some string
in place of
; indeed, let
be any
element of an infinite antichain or strictly decreasing sequence
in
.
Re-choose
if necessary to have the least possible
length. Write
. Clearly
is not empty, so
. Let
be the shorter string
(empty if
). Then
is wpo.
Now examine
. Let
be one of its elements. Since
, we
can write
, where
. In fact, by choosing
as short as possible in
turn (so that
stops just before the first element
that is
, etc.), we have
, for all
. Since
, we have
as well. In other words,
is an isotone image of part of
, so is wpo. But then
, which is the union of the wpo sets
and
, is also wpo, a contradiction.