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1. Composition of homogeneous linear transformations

Suppose $ T:$   R$ ^m \rightarrow$   R$ ^n$ and $ U:$   R$ ^k
\rightarrow$   R$ ^ m$ are h.l.t.'s. Then it makes sense to consider the composition $ T \circ U$ given by $ (T \circ U)($x$ ) =
T(U($x$ ))$. In terms of the matrices, if $ T = T _ A$ and $ U = T _ B$, then $ (T \circ U)($x$ ) = (T _ A \circ
T _ B) ($x$ ) = ($x$ B)A =$   x$ BA$. Thus composition of h.l.t.'s corresponds to matrix multiplication, but in reverse order1.

This explains in particular why matrix multiplication is associative, i.e., why $ (AB)C = A(BC)$: Composition is obviously associative, since $ (S \circ T)
\circ U$ and $ S \circ (T \circ U)$ applied to x are both just $ S(T(U($x$ )))$.





Kirby A. Baker 2002-01-10