5. Find the equation of the plane determined by the three points
(0,1,1), (1,0,1), (1,1,0).
Solution
: Letv = <1,0,1> - <0,1,1> = <1, -1, 0>
w = <1,1,0> - <0,1,1> = <1,0,-1>
The the normal to the plane, r, is given by
![]()

Consequently, the equation of the plane is
<1, 1, 1> · <x, y-1, z-1> = 0.
That is, x + y + z = 2.