(949, #1) Let S be the cube with vertices . Approximate

Solution: The centers of the sides of the cubes are at, respectivel (1,0,0), (-1,0,0), (0,1,0), (0,-1,0), (0,0,1) and (0,0,-1):

The integarl can be estimated by taking the value of the integrand,

(x2 +2 y2 + 3 z2)1/2 ,

at these six points and multiplying by the area of the face, which is 4 in each case.

Thus the approximation is

4( 1 + 1 + 21/2 + 21/2 + 31/2 + 31/2) = 33.17011496