(873, #9) Evaluate the triple integral
where E lies under the
plane z = x + 2 y and above the region in the xy-plane bounded
by the curves y = x2, y = 0, and x = 1.
Solution: The solid E is defined
in terms of the inequalities
| 0 <= z <= x + 2 y |
| 0 <= y <= x2 |
| 0 <= x <= 1 |
The latter two inequalities, 0
<= y <= x2 and 0 <= x <= 1, define the
base of the solid,which is displayed below at the left. For each
fixed (x, y) in this region z varies from0 to x + 2 y . The domain
of integration is outlined at the right.
Thus
The value of this integral is
5/28:
lprint(int(
y,z));
lprint(int( y,z = 0..x + 2*y));
y*z
x*y+2*y^2
lprint(int(int(
y,z = 0..x + 2*y),y));
lprint(int(int( y,z = 0..x + 2*y),y = 0 .. x^2));
1/2*x*y^2+2/3*y^3
1/2*x^5+2/3*x^6
lprint(int(int(int(
y,z = 0..x + 2*y),y = 0 .. x^2), x));
lprint(int(int(int( y,z = 0..x + 2*y),y = 0 .. x^2), x = 0..1));
1/12*x^6+2/21*x^7
5/28
by: gm