( 862, #15)
Find the center of mass of a lamina in the shape of an isosceles right triangle
with equal sides of length a if the density at any point is proportional
to the square of the distance from the vertex opposite the hypotenuse.
Solution:
For the sake of notational simplicity,
we take the constant of proportionality to be 1.
Then
The lamina's center of mass is ( 2a/5, 2a/5).
No Maple Code for this problem.
by: nl