(572,#5) Plot the point whose polar coordinates are (3,2). Then find two other pairs of polar coordinates of this point, one with r>0, and one with r<0.

Solution: The point (3,2) lies in the second quadrant at approximately 115 degrees because 2 radians=360/Pi

Two other pairs of polar coordinates of this point:

at r>0, rotating theta 360 degrees, we attain the same point with the coordinates =(3,2+2*Pi)

at r<0,rotating 180 degrees attains the same point with the coordinates (-3,2+Pi).

by:sh