Solution:
The distance from any point (x,y,z) to the point (0,0,0) is:
But if (x,y,z) lies on the surface
, we have:
Solving for the critical points,
Substituting A) into B),
Therefore, (0,0) is a critical point.
Using the Second Derivative Test,
So, is a local minimum.
Thus, the points on the surface closest to the origin are (0,0,1), (0,0,-1).
No Maple Code for this problem.
by:sh