Solution:
To find the critical points, solve the equations:
Substituting the values x = 0, y = -1 into B:
Therefore, the critical points are
Using the Second Derivative Test,
So, f(0,0) = 4 is a local minimum and
are saddle points.
Here is a graph of the function -f(x,y) where
the local minimum of f(x,y) is displayed as a maximum of -f(x,y).
The saddle points at
are also evident.
by:sh