(811, #37) Given the equation ,
a) find the tangent plane and
b) the normal line at the point .

Solution:

a)

The equation of the plane is , simplified: .

b) The normal line:

(x-1)/6 = (y - 0)/(-2) = (z-1)/2
That is,
(x-1)/3 = -y = z-1

No Maple Code for this problem.

by: gm