Solution:
Volume of a cylinder(tin can)
where r = radius = 4cm
h = height = 12cm
Applying the definition of the differential dz,
The differential of V is:
Suppose that the radius is decreased by 0.04 cm (dr = -0.04)
and the height is decreased by 0,08 cm
(dh = - 0.08). Then
dV = 96 Pi (-0.04) + 16 Pi (-0.08) = 16.08
This difference in volumes represents the space occupied by the tin of the can.
Thus the amount of tin is approximately
No Maple Code for this problem.
by: sh