(793,#31) Use differentials to estimate the amount of tin in a closed tin can with a diameter 8 cm and height 12cm if the tin is 0.04 cm thick.

Solution:

Volume of a cylinder(tin can)

where r = radius = 4cm

h = height = 12cm

Applying the definition of the differential dz,

The differential of V is:

Suppose that the radius is decreased by 0.04 cm (dr = -0.04) and the height is decreased by 0,08 cm
(dh = - 0.08). Then

dV = 96 Pi (-0.04) + 16 Pi (-0.08) = 16.08

This difference in volumes represents the space occupied by the tin of the can.

Thus the amount of tin is approximately

No Maple Code for this problem.

by: sh