we find that the traces on xz-plane are circles of radius
with its graph (labeled I-VIII). Give you reasons.
Solution: This is an equation of a hyperboloid of one sheet.
By rewriting the equation as
we find that the traces on xz-plane are circles of radius
Setting x or z equal to zero gives us
.
These are hyperbolas in the yz-plane and xy-plane.
The only possible graph is II.
by: gm