( 718, #65 ) Find the distance between the parallel planes z = x + 2y + 1 and 3x + 6y - 3z = 4.

Solution: A point must be found that lies on one of the planes. When y = x = 0 in the plane z = x + 2y + 1, there exists the point ( 0, 0, 1 ). To find the distance between the planes we can now use the equation for the distance between a point and a plane.

by: nl