(717, #23) Find an equation of the plane passing through the point ( 6, 5, -2) and parallel to the plane x + y -z + 1 = 0

(717, #25) Find an equation of the plane passing through the point ( -1, 3, -8) and parallel to the plane
3x - 4y -6z = 9.
Solution:
The normal vector for the plane is < 3, -4, -6 >. The general equation of a plane is:

or

or
3( x + 1 ) - 4( y - 3 ) - 6(z + 8 ) = 0

or
3x - 4y - 6z = 33

by: nl