(716, #21) Find an equation of the plane through the point ( 1, 2, 3 ) and with the normal vector n = 15i + 9j

(716, #21) Find an equation of the plane through the point ( 1, 2, 3 ) and with the normal vector
n = 15i + 9j - 12k.
Solution: The general equation of the plane

is in this particular case:

or
15( x - 1) + 9( y - 2) - 12(z - 3) = 0
or
15x + 9y - 12z = -3
or
5x + 3y - 4z = -1

by: nl

or 15( x - 1) + 9( y - 2) - 12(z - 3) = 0 or 15x + 9y - 12z = -3 or 5x + 3y - 4z = -1

or
15( x - 1) + 9( y - 2) - 12(z - 3) = 0
or
15x + 9y - 12z = -3
or
5x + 3y - 4z = -1