18. Let S be a set of real numbers such that l.u.b.(S) = 5/6 and g.l.b.(S) = 1/3, and let T = {-3x/2 | x belongs to S}. Then l.u.b.(T) =
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A. –3/2 |
B. –5/4 |
C. –5/9 |
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D. –1/2 |
E. –4/9 |
Solution: The answer is D
Given the least upper bound and the greatest lower bound of the set S, then any element x that belongs to S satisfies the following inequality,
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Thus, to find the least upper bound of T, multiply the above inequality by –3/2, so that,

This new inequality shows that the least upper bound of T is –1/2.