16. If z is the complex number such that (2 – i)z + 4 – 3i = 3iz, then z =
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A. –1 – (11/10)i |
B. –1 – (1/2)i |
C. –(1/3) + (5/6)i |
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D. (1/5) – (11/10)i |
E. (3/4) – (7/4)i |
Solution: The answer is B
Solve for z and use the complex conjugate to write z in standard form, a + bi, as follows:
