16. If z is the complex number such that (2 – i)z + 4 – 3i = 3iz, then z =

A. –1 – (11/10)i

B. –1 – (1/2)i

C. –(1/3) + (5/6)i

D. (1/5) – (11/10)i

E. (3/4) – (7/4)i

Solution: The answer is B

Solve for z and use the complex conjugate to write z in standard form, a + bi, as follows: