29.
|
A. 2 – ln(2) |
B. ln(2) – 1/2 |
C.2 tan2(2) + 4 ln[cos(2)] |
|
D. 2 ln[sec(2)]-sin2(2) |
E. 2 - p /2 |
|
Solution: The answer is E
Add and subtract four to the numerator of the integrand to rewrite the integral as follows,
Use the properties of integrals to obtain
Since,
We have the following solution,
