20. Let S be the closed region in the first quadrant of the xy-plane bounded by y = 6x2, y = 0, x = 0, and x = 1. What is the volume of the solid obtained by revolving S about the line x = -1?
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A. 3p |
B. 7 p |
C. 36 p /5 |
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D. 8 p |
E. 56 p /5 |
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Solution: The answer is A
Rotating a vertical differential piece within the enclosed region of thickness dx about the line x = -1 creates a thin walled open cylinder with height y, whose differential volume, dV, is given by,
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Integrate the above equation over the interval [0,1] to obtain the total volume created by rotating the entire region. That is,
