15.
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A. ln (1 + e-1) |
B. - ln (1 + e-1) |
C. ln (1 + e) |
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D. arctan (e1/2) |
E. does not exist |
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Solution: The answer is A
The given integral,
is an improper integral whose value is given by,

Letting,

Thus, taking the limit as b goes to infinity yields,
