12. A point moves along a number line so that its position at time t >= 0 is s(t) = 2t3 – 15t2 + 36t – 10. What is the position of the point when it first changes direction?
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A. -63 |
B. 0 |
C. 17 |
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D. 18 |
E. 98 |
Solution: The answer is D
First find the critical points by solving s’(t) = 0.
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Let the two critical points divide the domain of definition into three subintervals and determine the sign of s’(t) within each interval. A change in sign implies a change in direction at the corresponding critical point. As demonstrated by the following graph:

Thus, the position of the point when it first changes direction is given by, solving s(2) as follows:
