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\LARGE
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\title{\Huge{\bf The Mackey doctrine}}   
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\author{\Huge Greg Hjorth}      
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\date{\LARGE{1997}}          % Enter your date or \today between curly braces
\maketitle

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%\newpage

\Huge

\noindent{\bf $\S$ 0 Definition}

\noindent \Large{ The name of George Mackey is often associated with the view that an equivalence relation 
is {\it classifiable} if there is a `nice', preferably Borel, function that assigns 
points in a very concrete space -- 
$\Large{\Bbb{R}}$,$ \Bbb C,{\mathbb T}, C([0,1])$ -- as a complete 
invariant. }

\bigskip 

\noindent {\bf 0.1 Definition} Let $E$ be an equivalence relation on a  separable, completely metrizable 
(that is {\it Polish}) space $X$. $E$ is {\it concretely classifiable} if there is a Borel 
function  
\[ \theta:X\rightarrow {\Bbb R}\]
such that for all $x,y\in X$ 
\[xEy\Leftrightarrow \theta(x)=\theta(y).\]

\medskip

\newpage 

\noindent {\bf 0.2 Remarks:} (i) It may be helpful to think of 
\[ \theta:X\rightarrow {\Bbb R}\]
 as lifting to an injection 
\[ \hat{\theta}:X/E\rightarrow {\Bbb R},\]
and that in this sense the {\it Borel cardinality} of $X/E$ is less than or equal to the 
Borel cardinality of ${\Bbb R}$. 


(ii) Here a function is {\it Borel} if the preimage of any open 
set is Borel (that is to say, in the $\sigma$-algebra generated by the 
open sets). 

(iii) The existence of $\theta$ as above is equivalent to there being a countable 
sequence $(A_n)_{n\in{\Bbb N}}$ of $E$-invariant Borel sets such that 
\[xEy\]
if and only if 
\[\{n: x\in A_n\}=\{n: y\in A_n\}.\]

(iv) Another equivalent formulation is that $X/E=\{[x]_E:x\in X\}$ be a 
{\it standard Borel space} in the quotient Borel structure -- 
that is to say, there is a Polish topology on $\tau$ on $X/E$ such that 
the Borel sets in $(X/E,\tau)$ are exactly the images of the $E$-invariant 
Borel sets in $X$. 

\newpage 

\noindent {\bf $\S$1 Examples (concretely classifiable)} 

\medskip 

\noindent {\bf 1.1 Example ($n$-dimensional linear operators)} Let $H_n$ be $n$-dimensional complex Hilbert space, 
$U_n$ be the space of unitary operators over $H_n$, and consider the problem 
of classifying these objects up to conjugation: 
\[A_1\sim A_2 \Leftrightarrow \exists B\in U_n(BA_1B^{-1}=A_2).\]

Here the list of eigenvalues $(\lambda_1,\lambda_2,...,\lambda_n)$ in increasing 
order with multiple eigenvectors repeated provides a complete invariant. Since there 
is a Borel injection from ${\Bbb C}^n$ into ${\Bbb R}$, we obtain a concrete classification. 

\medskip 
\newpage 

\noindent {\bf 1.2 Example (Bernoulli shifts)} 
Let $S=\{s_1,...,s_n\}$ be a finite alphabet, $\sigma: S^{\Bbb Z}\rightarrow 
S^{\Bbb Z} $ be the shift map, and for $p_1, p_2,...,p_n$ a finite sequence of positive 
numbers summing to 1 let $\mu$ the product measure resulting from these weights. 
We may choose to think of two such systems as being equivalent if there is an invertible 
measure preserving map that conjugates them: that is, set $(S_1, \sigma_1, \mu_1)\cong 
(S_2, \sigma_2, \mu_2)$ if there is a measurable preserving bijection 
\[\pi:  (S_1)^{\Bbb Z}\rightarrow (S_2)^{\Bbb Z}\]
such that 
\[\sigma_1=\pi^{-1}\circ \sigma_2 \circ \pi\]
\[\forall A\subset (S_2)^{\Bbb Z}(\mu_2(A)=\mu_1(\pi^{-1}(A))).\]

Ornstein\footnote{\large{{\it Bernoulli shifts with the same entropy are isomorphic,} 
({\bf Advances in Mathematics,} vol. 4(1970), pp. 337-52)}} 
showed that here a single real number, the {\it entropy} of the system 
$(S, \sigma, \mu)$, provides a complete invariant. (Moreover, in a suitable standard 
Borel structure, this invariant can be calculated in a Borel fashion.) 


\medskip 
\newpage 

\noindent {\bf 1.3 Example (group representations)} Consider the irreducible representations 
of the group ${\Bbb Z}$. Given a 
complex Hilbert space $H$ with associated unitary group $U$ of all inner product respecting 
transformations, we can let Irr$({\Bbb Z}, H)$ be the space of homomorphisms 
\[\tau: {\Bbb Z}\rightarrow U\]
where $U$ has no non-trivial invariant subspaces under $\tau[{\Bbb Z}]$. It is natural to 
think of $\tau_1$ and $\tau_2$ as somehow presenting equivalent representations if there is 
some $A\in U$ with  
\[\tau_1(g)=A^{-1}\circ \tau_2(g)\circ A\]
for all $g\in {\Bbb Z}$. 

Here  Irr$({\Bbb Z}, H)$ is non-empty if and only if $H$ is one dimensional. Moreover  we 
may identify the elements of Irr$({\Bbb Z}, H)$ with characters, and thus a complete classification 
of these objects may be given by points in ${\Bbb T}$, and hence ${\Bbb R}$. 

On the other hand if $G$ is finite the space Irr$(G, H)$ will be non-empty only when 
$H$ is finite dimensional. Then the above equivalence relation will be induced by the a continuous 
action of the now compact group $U$ 
on the Polish space Irr$(G, H)$. In general such orbit equivalence 
relations are always classifiable by points in ${\Bbb R}$. 

More generally, it is known that whenever $G$ is a countable abelian-by-finite group 
the above equivalence relation on Irr$(G, H)$ is concretely classifiable. 






\newpage 

\noindent {\bf $\S$2 Non-Examples (not concretely classifiable)} 

\medskip 

\noindent {\bf 2.1 The Vitali equivalence relation} For $x, y\in {\Bbb R}$ set 
\[xE_v y\]
if and only if 
\[x-y\in{\Bbb Q}.\]
So certainly there is no Lebesgue measurable selector. In fact one can show the stronger 
result that any Lebesgue measurable ${\Bbb Q}$-invariant $\theta:{\Bbb R}\rightarrow {\Bbb R}$ is 
constant a.e. In particular, $E_v$ 
is {\it not} concretely classifiable. 

A similar example is given by the equivalence relation of eventual agreement on the 
Cantor space -- $\{0,1\}^{\Bbb N}$ in the product topology. Given $x, y:{\Bbb N}\rightarrow 
\{0,1\}$ set 
\[xE_0y \]
if and only if there is some $K$ such that for all $m>K$ 
\[x(m)=y(m).\]
Any $E_0$-invariant Borel $\theta: \{0,1\}^{\Bbb N}\rightarrow {\Bbb R}$ must be constant on a 
comeager set. 

\newpage 

\noindent {\bf 2.2 Group representations again} 
Let $G$ be a countable discrete group that it {\it not} abelian-by-finite. Let $H_{\infty}$ be a 
separable infinite dimensional Hilbert space and $U_{\infty}$ the unitary group on 
$H_{\infty}$. Again take  Irr$(G, H_{\infty})$ to be space of irreducible 
representations $\tau:G\rightarrow U_{\infty}$ with the equivalence relation of 
conjugacy -- 
\[\tau_1\approx \tau_2\Leftrightarrow \exists A\in U_{\infty}\forall g\in G
(\tau_1(g)=A^{-1}\circ \tau_2(g)\circ A).\] 
$\approx$ is not concretely classifiable: there is no Borel assignment of reals as 
complete invariants to Irr$(G,H_{\infty})/\approx$.\footnote{\large{J. Glimm, 
{\it Type I $C^*$-algebras,} 
{\bf Annals of Mathematics,} 1961, pp. 572-612; E. Thoma, {\it Eine Charakterisierung diskreter 
Gruppen vom Type I,} {\bf Inventiones Mathematicae} vol. 6(1960), pp. 190-6}}


\bigskip 


\noindent {\bf 2.3 Complex Domains} J. Becker, W. Henson, and L. Rubel  
\footnote{\large{{\it First-order conformal invariants,} 
({\bf Annals of Mathematics,} 1980, pp. 123-178)}} obtain non-classifiability 
by embedding the equivalence relation $E_0$ of eventual agreement on infinite 
sequences of 0's and 1's into conformal equivalence on complex domains. 

In fact if we assign ${\cal D}$, the space of 
open subsets of ${\Bbb C}$, with the {\it Effros standard Borel structure} -- under 
which it does have a natural Borel structure -- then their argument can be seen 
as showing that there is a Borel function 
\[\theta:\{0,1\}^{\Bbb N}\rightarrow {\cal D}\]
such that $xE_0y$ if and only if $\theta(x)$ and $\theta(y)$ are biholomorphic. 





\newpage 

\noindent {\bf $\S$3 More Examples (puzzling cases)} 

\medskip 

\noindent {\bf 3.1 Discrete spectrum mpt's} 
Let $M_{\infty}$ be the space of all measure preserving invertible transformations 
of the unit interval. This is a {\it Polish group} -- that is to say a 
topological group that is Polish as a space; for instance, if $(U_n)$ enumerates the 
basic open subsets of $[0,1]$ we obtain a complete metric with 
\[d(\pi_1, \pi_2)=\sum_{n\in{\Bbb N}}2^{-n}\lambda(\pi_1(U_n)\Delta\pi_2(U_n))+
\lambda(\pi_1^{-1}(U_n)\Delta\pi_2^{-1}(U_n)).\]


We may try to classify measure preserving transformations of 
the unit interval, or any other probability space. Here consider  
$\pi_1, \pi_2:[0,1]\rightarrow [0,1]$ {\it equivalent} if conjugate -- 
so there is some $\sigma:[0,1]\rightarrow [0,1]$ 
such that 
\[\sigma\circ\pi_1=\pi_2\circ\sigma {\rm {a.e.}}\]  
P. R. Halmos and J. von Neumann 
\footnote{\large{{\it Operator methods in 
classical mechanics, II} ({\bf Annals of Mathematics,} 
vol. 43(1942), pp. 332-50)}} 
showed that for {\it discrete spectrum} mpt's, we may in a Borel fashion 
assign a countable collection $\{c_i(\pi):i\in{\Bbb N}\}$ of complex numbers that 
completely describe the equivalence class of $\pi$. 
While conjugacy on discrete measure preserving transformations is not 
concretely classifiable, 
the Halmos-von Neumann theorem would seem to constitute some sort of weaker notion of 
classification. 


\newpage  





\noindent {\bf 3.2 Conformal domains} Becker-Henson-Rubel explicitly ask: is there some reasonably 
non-pathological way to assign to every domain $D\subset {\Bbb C}$ some countable set of complex 
numbers $S_D$ such that 
\[D\cong D'\]
if and only if 
\[S_D=S_{D'}?\]

\newpage 

\noindent {\bf 3.3 $C^*$ algebras and topological dynamics} 
 T. Giordano, I.F. Putnam, and C.F. Skau
\footnote{\large{{\it Topological orbit equivalence 
and $C^*$-crossed products} ({\bf Journal Reine und Angewandt Mathematische,} 
vol. 469(1995), pp. 51-111)}} 
consider the problem of classifying {\it minimal Cantor systems up to orbit equivalence}. 
Two continuous 
\[\varphi_1:X_1\rightarrow X_1,\] 
\[\varphi_2:X_2\rightarrow X_2\] 
which are {\it minimal} in 
the sense of having no 
non-trivial closed invariant sets and are {\it Cantor} in the 
sense of $X_1$, $X_2$ being compact, uncountable and 
completely disconnected metric spaces, are said to be {\it orbit equivalent} if 
there is a homeomorphism $F:X_1\rightarrow X_2$ which respects 
the orbits structure set wise, in that for all $x$ 
\[\{\varphi_2^{i}(F(x)):i\in{\Bbb Z}\}=F[\{\varphi_1^{i}(x):i\in{\Bbb Z}\}].\] 
This problem is in turn equivalent to classifying a certain class 
of $C^*$-algebras. 

Here they produce countable ordered abelian groups as complete invariants. 

\newpage

\noindent {\bf 3.4 Question} For which equivalence relations can we provide a countable 
set of reals as a complete invariant? So given a Polish space $X$ (separable and 
completely metrizable), and equivalence relation $E$, 
when can we find a countable sequence $(f_i)_{i\in{\Bbb N}}$ of 
Borel functions 
\[f_i:X\rightarrow {\Bbb R}\]
such that 
\[xEy\Leftrightarrow \{f_i(x):i\in{\Bbb N}\}=\{f_i(y):i\in{\Bbb N}\}?\]


\medskip 


More generously, for which $E$ can we provide some 
kind of countable structure considered up to isomorphism as a complete invariant? 

Letting ${\cal L}$ be a countable language, we can form 
Mod$({\cal L})$, the space of all ${\cal L}$-structures on ${\Bbb N}$ with the topology 
generated by quantifier free formulas. For which equivalence relations $E$ can we 
find a Borel 
\[\theta:X\rightarrow {{\rm{ Mod}}({\cal L})}\]
such that for all $x, y\in X$ 
\[xEy\Leftrightarrow \theta(x)\cong \theta(y)?\]


\bigskip 

{\bf 3.5 Remark} Most mathematical objects can be at least {\it parameterized} by 
points in a Polish space in a reasonable fashion. 

\newpage 






\noindent{\bf $\S$4 Sufficient conditions for classifiability} 

\medskip 

\noindent {\bf 4.1 Fact} Let $G$ be a compact metrizable group acting continuously on a Polish 
space $X$ with induced orbit equivalence relation $E_G$. Then $E_G$ is concretely 
classifiable -- that is to say, there is Borel $\theta:X\rightarrow {\Bbb R}$ such that 
for all $x, y\in X$
\[\exists g\in G(g\cdot x=y)\Leftrightarrow \theta(x)=\theta(y).\] 

\bigskip 
\bigskip 


\bigskip 
\bigskip 


\noindent {\bf 4.2 Theorem} (Kechris) Let $G$ be a locally compact Polish group acting continuously 
on a Polish space $X$. Then there is a countable sequence of Borel functions  $(f_i)_{i\in{\Bbb N}}$ 
such that for all $x,y\in X$ 
\[xE_Gy\Leftrightarrow \{f_i(x):i\in{\Bbb N}\}=\{f_i(y):i\in{\Bbb N}\}.\] 


\bigskip 
\bigskip 



It turns out that conformal equivalence on complex domains, or even arbitrary 
complex surfaces, may be reduced to an appropriately chosen locally compact 
group action. 


\newpage


\noindent {\bf 4.3 Theorem} (Hjorth-Kechris) Let ${\cal D}$ be the space of all complex domains.  
(a) Then there is a {\it definable} (in the language of ZFC) assignment 
\[M\mapsto S_M\]
of countable sets of reals to domains such that for all $M, N\in {\cal D}$ 
\[M\cong N\Leftrightarrow S_M=S_N.\] 

(b) The above assignment extends to a space of parameters for complex surfaces, 
is Borel in a natural Borel structure, and conformal equivalence is 
bireducible with 
$C({\Bbb F_2}, {\Bbb Z})/{\Bbb F_2}$. 


\bigskip 
\bigskip 

The description of the Borel space of parameters for complex surfaces is somewhat 
involved. But for the specific case of ${\cal O}({\Bbb C})$ the set of open subsets of 
of ${\Bbb C}$ we can take the {\it Effros standard Borel structure}, generated 
by the sets of the form 
\[\{O\in {\cal O}({\Bbb C}): U\subset O\}\]
for $U\subset {\Bbb C}$ open. Here it is known that there are Polish topologies on 
${\cal O}({\Bbb C})$ with this Borel structure. 

In this Borel structure we may obtain a countable sequence of Borel 
\[f_i: {\cal O}({\Bbb C})\rightarrow {\Bbb R}\]
such that 
$O_1$ and $O_2$ are conformally equivalent if and only if 
\[\{f_i(O_1):i\in{\Bbb N}\}=\{f_i(O_2):i\in{\Bbb N}\}.\]

\newpage 


\noindent {\bf $\S$5 Sufficient conditions for non-classifiability} 

\bigskip 


\noindent {\bf 5.1 Theorem} (folklore) Let $G$ be a Polish group and $X$ a Polish space. Suppose that  

(i) some orbit is dense; 

(ii) every orbit is meager (its complement includes the intersection of 
countably many open dense sets). 
Then $E_G$ is not concretely classifiable: there is no 
Borel (or even Baire measurable) 
\[\theta:X\rightarrow {\Bbb R}\]
such that for all $x, y\in X$ 
\[\exists g\in G(g\cdot x=y)\Leftrightarrow \theta(x)= \theta(y).\]

\newpage 

\noindent {\bf 5.2 Theorem} (Hj.) Let $G$ be a Polish group and $X$ a Polish space. Suppose that  

(i) some orbit is dense; 

(ii) every orbit is meager (its complement includes the intersection of 
countably many open dense sets); 

(iii) for all $x\in X$, {\it the local orbits of $x$} are somewhere dense; that is to 
say, if $V$ is an open neighborhood of $1_G$, $U$ is an open set containing $x$, and 
if $O(x,U,V)$ is the set of all $\hat{x}\in [x]_G$ such that there is a finite sequence 
$(x_i)_{i\leq k}\subset U$ such that $x_0=x$, $x_k=\hat{x}$, and each $x_{i+1}\in V\cdot x_i$, 
then  the closure of $O(x,U,V)$ contains an open set. 

Then there is no 
Borel (or even Baire measurable) 
\[\theta:X\rightarrow {{\rm{ Mod}}({\cal L})}\]
such that for all $x, y\in X$ 
\[xE_Gy\Leftrightarrow \theta(x)\cong \theta(y).\] 

Consequently there is no sequence $(f_i)_{i\in{\Bbb N}}$ of 
Borel functions 
\[f_i:X\rightarrow {\Bbb R}\]
such that 
\[xEy\Leftrightarrow \{f_i(x):i\in{\Bbb N}\}=\{f_i(y):i\in{\Bbb N}\}.\]

\newpage 

The method of proof succeeds for classes of functions considerably more 
complicated than Borel. 

By interpreting such an orbit equivalence relation into isomorphism on higher 
dimensional manifolds one can obtain theorems like: 

\bigskip 

\noindent {\bf 5.3 Theorem} (Hj.-Kechris) Let ${\cal M}^2$ be the space of two dimensional 
complex manifolds. Then (consistently) there is no definable assignment of countable 
sets of reals as complete invariants. 


\bigskip 
\bigskip 

\bigskip 
\bigskip 



\bigskip 
\bigskip 




\noindent \underline{Class of complex manifolds} \hfill \underline{Invariants} 


\bigskip 
\bigskip 



\noindent Compact complex surfaces \hfill points in ${\Bbb R}$ 

\noindent General complex surfaces \hfill countable subsets of ${\Bbb R}$ 

\noindent General complex manifolds \hfill ?[none of the above]

\newpage 




\newpage 

\noindent {\bf 5.4 Theorem} (Hj.) Let $M_{\infty}$ be the space of invertible measure preserving 
transformations on the unit interval. Consider the conjugacy equivalence relation 
$\sim$: $\pi_1\sim \pi_2$ if there is $\sigma\in M_{\infty}$ such that 
\[\sigma\circ\pi_1=\pi_2\circ\sigma \: {\rm {a.e.}}\]  

Then there is no sequence $(f_i)_{i\in{\Bbb N}}$ of 
Borel functions 
\[f_i:M_{\infty}\rightarrow {\Bbb R}\]
such that 
\[\pi_1\sim\pi_2\Leftrightarrow \{f_i(\pi_1):i\in{\Bbb N}\}=\{f_i(\pi_2):i\in{\Bbb N}\}.\]

In fact, $\sim$ is strictly more complicated than isomorphism on countable models: there is a 
Borel 
\[\theta:{{\rm{ Mod}}({\cal L})}\rightarrow M_{\infty}\]
such that for all $M,N\in {\rm{ Mod}}$ 
\[M\cong N\Leftrightarrow \theta(x)\sim \theta(y),\] 
but (for any choice of ${\cal L}$) there is no 
\[\theta:M_{\infty}\rightarrow {{\rm{ Mod}}({\cal L})}\]
such that for all $\pi_1,\pi_2\in M_{\infty}$ 
\[\pi_1\sim \pi_2\Leftrightarrow \theta(x)\cong \theta(y).\] 





\noindent {\bf 5.5 Theorem} (Hj.) Let $G$ be a countable group that is {\it not} 
abelian-by-finite. Let $H_{\infty}$ be an separable infinite dimensional Hilbert space, 
let Irr$(G, H_{\infty})$ be the space of irreducible representations of $G$ in 
$H_{\infty}$. For $\tau_1\approx\tau_2$ if there is $A\in U(H_{\infty})$, the 
unitary group on $H_{\infty}$, that conjugates them in the sense that for all $g\in G$ 
\[\tau_1(g)=A^{-1}\circ \tau_2(g)\circ A.\] 

Then there is no sequence  $(f_i)_{i\in{\Bbb N}}$ of 
Borel functions 
\[f_i:{\rm {Irr}}(G,H_{\infty})\rightarrow {\Bbb R}\]
such that 
\[\tau_1\approx\tau_2\Leftrightarrow \{f_i(\tau_1):i\in{\Bbb N}\}=\{f_i(\tau_2):i\in{\Bbb N}\}.\]

In fact there is no {\it reasonably definable} assignment of countable models considered 
up to isomorphism as complete invariants. 



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