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\title{\Huge {\Huge Borel equivalence relations}}        

\author{{\Huge Greg Hjorth}\\{\LARGE greg@math.ucla.edu}}        % Enter your name between curly braces
\date{\huge September 2003, Barcelona}          
\maketitle

\pagestyle{myheadings} 
\markright{\large Borel} 

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{\bf $\S$1. Definitions. Examples} 

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\n {\bf Definition} A 

\centerline{{\it Polish space}}

\n is a completely 
metrizable separable space. 

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\n Its 


\centerline{{\it Borel sets}} 

\n are those 
appearing in the $\sigma$-algebra generated by the open sets. 

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\n $(X, \b)$ is a 

\centerline{{\it standard Borel space}} 

\n if $\b$ is the collection of Borel 
sets for some Polish topology on $X$. 


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%Sometimes there is  a canonical 
%standard Borel structure, but no canonical choice of a Polish topology. 

\newpage 


\n {\bf E.g. 1} $\R$ and $\C$ are Polish. Any compact metric space is Polish. 

\bigskip 

\n {\bf E.g. 2} There is a natural way to think of the collection of all subsets 
of the natural numbers as a Polish space. By associating with each 
set its characteristic function, or indicator function, 
we can identify the power set of $\N$, 
denoted by $\p (\N)$, with 
\[\{0, 1\}^\N=_{\rm df} 2^\N,\] 
which is a compact space in the product topology. 
Similarly $\p(\N\times\N)$ or $\p(S)$ any countable set $S$. 




\bigskip 


\newpage 

\n {\bf E.g. 3} Any Borel subset of a Polish space is a standard Borel space 
in the inherited Borel structure 
(see e.g. Kuratowski's {\it Topology}). 


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\n {\bf E.g. 4} The Borel probability measures on a standard Borel space 
themselves again form a standard Borel space. 

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\n {\bf E.g. 5} Consider the 
collection of subsets of $\N\times\N\times \N$ which form the graph of 
function 
\[\bullet : \N\times \N\rightarrow \N\] 
providing a finite rank torsion free abelian group structure on $\N$. This 
collection in the natural Borel structure is a standard Borel space. 

\bigskip 

\bigskip 

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\newpage 

\n {\bf Definition} A function 
\[f: X\rightarrow Y\] 
is said to be {\it Borel} if $f^{-1}[B]$ is Borel for any Borel 
set $B\subset Y$. 
An equivalence relation $E$ on $X$ is said to be {\it Borel} 
if it is Borel as subset of $X\times X$. 

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\n {\bf Definition} Given $E$ and $F$ Borel equivalence relations 
on standard Borel $X$ and $Y$, 
we write 
\[E\leq_B F,\] 
$E$ is {\it Borel reducible to} $F$, if there is a Borel $f:X\rightarrow Y$ 
such that for all $x_1, x_2\in X$ 
\[x_1 E x_2 \Leftrightarrow f(x_1) F f(x_2);\] 

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\n in other words, $f$ pushes down to injective map 
\[\bar{f}: X/E \rightarrow Y/F\] 
between the quotient spaces. 





\newpage 


\n {\bf Remark} This definition is only for Borel $f$, but one can of course 
consider more general classes of functions if this seems too stingy -- 
for instance, $C$-measurable functions, 
projective functions, $L(\R)$ functions. In virtually all cases this makes 
no difference -- the failures of reducibility for Borel functions persist 
to these wider classes. 
Indeed, appropriately understood most of the theorems about Borel 
equivalence relations turn into theorems about cardinality in $L(\R)$. 


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\n {\bf Another remark} If $f$ witnesses $E\leq_B F$ it may be the case 
that $f$ is much more complicated than $E$ and $F$. That is okay. We don't care 
about the complexity of $f$ as long as it is reasonable. 

$E\leq_B F$ does not necessarily mean that $E$ is simpler than $F$. 

\bigskip 
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\newpage 


{\bf $\S$2. Examples} 

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\n {\bf E.g. 1} For $X$ a standard Borel space, 
id$(X)$ is the identity relation on $X$. 

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\n {\bf Fact} (Classical) If $X$ is an uncountable standard Borel space 
then 
\[ {\rm id}(X)\sim_B{\rm id}(\R).\] 

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That is to say, each is Borel reducible to the other. 
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\n {\bf Theorem}(Silver) If $E$ is Borel, then either: 

\leftskip 0.6in 

\n (I) $E\leq_B$ id$(\N)$; or 
 
\n (II) id$(\R)\leq_B E$. 

\leftskip 0in 


\bigskip 
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\newpage 

\n {\bf E.g. 2} Let $E_v$ be the coset equivalence relation 
of $\Q$ in $\R$: 

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$r_1 E_v r_2$ if 
\[r_1- r_2\in \Q.\] 

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Let $E_0$ be defined on $\p(\N)$ by $A E_0 B$ if 
their symmetric difference, 
\[A\Delta B=_{\rm df} (A-B)\cup (B- A),\] 
is finite. 


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\n {\bf Fact:} $E_0\sim_B E_v$. 

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(I.e. each is $\leq_B$ reducible to the other.)  

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id$(\R)<_B E_0$. 

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(I.e. reduction in one direction but not the other.) 

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\newpage 

\n {\bf E.g. 3} Let $\l$ be the language generated by 
$\aleph_0$ many unary predicates. Let Mod$(\l)$ be the 
$\l$-structures with underlying set $\N$ and let 
\[F_2\] 
be the isomorphism relation 
\[\cong|_{{\rm Mod}(\l)}\] 
on these structures. 

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Even though from the point of model theorists the classification problem 
for a language with countably many unary predicates is usually considered to 
be relatively easy, one already has: 

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\[{\rm id}(\R)<_B E_0 <_B F_2.\] 

\newpage 

\n {\bf E.g. 4} Let $U_\infty$ be the unitary group on $\ell_2$, consisting of 
linear isometries of $\ell_2$ onto $\ell_2$. Let $\sim_{U_\infty}$ be the conjugacy 
equivalence relation on operators in $U_\infty$ -- so two unitary operators are 
$\sim_{U_\infty}$ if and only if they are look the same up to a unitary ``reshuffling" 
of $\ell_2$. 

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Let $M([0,1])$ be the collection of all probability measures on the unit interval. 
Let $\sim^*$ be the equivalence relation of mutually continuity -- that is to say, 
$\mu \sim^* \nu$ if they have the same null sets. 

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\n {\bf Theorem} (In effect, Gelfand) 



\[\sim^*\leq_B  \sim_{U_\infty}\]
\[\sim_{U_\infty}\leq_B \sim^*.\] 

 

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\n {\bf Theorem} (Kechris) 



\[F_2 <_B \sim^*.\] 

\newpage 

\n {\bf E.g. 5} Let $\cong_n$ be the isomorphism relation on rank $n$ torsion 
free abelian groups. (Up to isomorphism, these are all subgroups of 
$\Q^n$.) 

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\n {\bf Theorem} (In effect, Baer; early 1900's) 

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$\cong_1\sim_B E_0$. 



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That is to say, each is Borel reducible to the other. 

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\n {\bf Theorem} (Thomas, c. 2001) 

For {\it all } $n$ 
\[\cong_n <_B \cong_{n+1}.\] 

\newpage 

\n {\bf E.g. 6} Let $\equiv_T$ be Turing equivalence on subsets of $\N$ -- that is to say, 
set $A \equiv_T B$ if each is computable from the other. 

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Very little is known about the precise position about $\equiv_T$ beyond a few initial 
facts such as 
\[E_0 <_B \equiv_T <_B F_2.\] 

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In a paper from the 80's Slaman 
and Steel ask for something along the lines of the following:- 

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\n {\bf Question} Let $\F$ be a countable non-abelian free group. Does there exist a free action 
of $\F$ by isometries on a compact metric space with the resulting equivalence relation $E_\F$ 
having 
\[E_\F\leq_B \equiv_T?\] 





\newpage 

{\bf $\S$3. The picture so far} 

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At the very bottom of the picture we have Silver's theorem. 

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\n {\bf Theorem} (Silver, 1970's) If $E$ is Borel, then either: 

\leftskip 0.6in 

\n (I) $E\leq_B$ id$(\N)$; or 
 
\n (II) id$(\R)\leq_B E$. 

\leftskip 0in 

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Then: 

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\n {\bf Theorem} (Harrington-Kechris-Louveau, 1989) If $E$ is Borel, then either: 

\leftskip 0.6in 

\n (I) $E\leq_B$ id$(\R)$; or 
 
\n (II) $E_0\leq_B E$. 

\leftskip 0in 

\newpage 


\n {\bf ASIDE:} 

\bigskip 

Both these theorems turn into theorems about $L(\R)$ cardinality 
under determinacy assumptions. 

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For instance (Woodin) with Silver's theorem we obtain that any set in $A\in L(\R)$ is either 
wellorderable in $L(\R)$ or has 
\[|2^\N|_{L(\R)}\leq_{L(\R)} |A|_{L(\R)}\] 
in the sense of their being an injection in $L(\R)$ of $2^\N$ into $A$. 

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Harrington-Kechris-Louveau turns into the statement that for any $A\in L(\R)$ either we 
have some ordinal $\alpha$ with 
\[|A|_{L(\R)}\leq_{L(\R)} |{{\mathcal P}}(\alpha)^{L(\R)}|_{L(\R)}\] 
or 
\[|{\mathcal P}(\N)/{\rm Fin}|_{L(\R)}\leq _{L(\R)} |A|_{L(\R)}.\] 

\newpage 





After this there are no outright dichotomy theorems of exactly this form 
(that is to say, of the form {\it either $E$ is below some canonical example or it is above 
some other canonical example}). 
There are at least some immediate successor 
nodes to $E_0$. 

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\n {\bf Definition} For 
\[\vec x=(x_1, x_2,...)\in (2^\N)^\N,\] 
\[\vec y=(y_1, y_2,...)\in (2^\N)^\N,\] 
set $\vec x E_1 \vec y$ if for all sufficiently large $n$ we have 
\[x_n=y_n.\] 
Set $\vec x (E_0)^\N \vec y$ if at {\it every $n$} 
\[x_n E_0 y_n.\] 

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Here we have $E_0<_B E_1$ and $E_0<_B (E_0)^\N$, and moreover these are both 
immediate successors. 

\newpage 

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\n {\bf Theorem} (Kechris-Louveau, 1992) If $E\leq_B E_1$ then either 

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\n (I) $E\leq_B E_0$, or 

\n (II) $E_1\leq_B E$. 

\leftskip 0in 

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\n {\bf Theorem} (H-Kechris, 1996) If $E\leq_B (E_0)^\N$ then either 

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\n (I) $E\leq_B E_0$, or 

\n (II) $(E_0)^\N\leq_B E$. 

\leftskip 0in 

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These are the only immediate successors to $E_0$ known at the present time. 

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Following work of Ilijas Farah, who produced examples motivated by ideas 
in Banach space theory, it appears that there are promising 
candidates for continuum 
many immediate successors. 

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\newpage 

One can also try for ``local dichotomy" theorems: 

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\n {\bf Theorem} (1999) If $E$ is Borel reducible to the isomorphism relation on 
some countable structures, then either: 

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\n (I) $E$ is Borel reducible to some equivalence relation all of whose classes 
are countable; or

\n (II) $(E_0)^\N\leq_B E$. 

\leftskip 0in 

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%There is at least one other faintly plausible candidate for a theorem of this 
%nature. 

%\newpage 

%\n {\bf Question} If $E$ is Borel, must it be the case that 
%either 

%\leftskip 0.6in 

%\n (I) $E\leq E_G$ where $E_G$ arises from the continuous action 
%of some Polish group\footnote{That is to say, a topological group which 
%is separable and completely metrizable.} on some Polish space $X$, or 

%\n (II) $E_1\leq_B E$? 

%\leftskip 0in 

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%It was shown by Louveau and Kechris that $E_1$ is never Borel reducible to some 
%such $E_G$, so this is a bit like asking whether $E_1$ is the canonical obstruction 
%to being reducible to a Polish group action. 

\newpage 


\n {\bf Recent work on countable equivalence relations} 

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\n {\bf Definition} A Borel equivalence relation is {\it countable} if all of its 
equivalence classes are countable. It is {\it essentially countable} if it is 
$\leq_B$-reducible to some countable equivalence relation. 


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It turns out that these are in some sense distinct notions up to Borel reducibility. 
Just over summer it was realized that: 

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\n {\bf Theorem} There is an essentially countable Borel equivalence relation $E$ 
such that for no countable Borel equivalence relation $F$ do we have 
\[E \sim_B F.\] 

\newpage 

A countable Borel equivalence relation is said to be {\it treeable} if there is a 
Borel way to assign a 
tree structure (without any distinguished root) 
to each equivalence class -- thus, $E$ on $X$ is 
treeable if there is a Borel graph 
\[G\subset X\times X\] 
such that $G$ has no loops and its connected components are the $E$-equivalence 
classes. 

\newpage 

\n {\bf E.g.1} $E_0$ is countable. 

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\n {\bf E.g. 2} The various $\cong_n$'s (isomorphism on finite rank 
torsion free abelian groups) are essentially countable. 

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\n {\bf E.g. 3} Any free, Borel 
action of $\F_2$ (the free group on two generators) gives rise to a treeable 
orbit equivalence relation. 


\newpage 

\n {\bf A strange empirical fact} 

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Practically all known constructions of countable Borel equivalence relations which 
are $\leq_B$-distinguishable involve ergodic theoretic techniques. They 
come down to finding \[E_G, \: \: \:  E_H\] 
arising from ergodic (that is to say, any invariant 
measurable set is null or conull), measure preserving actions of countable 
groups $G, H$ on standard Borel probability spaces 
\[(X, \mu), \:\:\: (Y, \nu)\] 
such that on 
{\it any} invariant 
measure one 
\[X_0\subset X\] we have that the induced orbit equivalence relation 
$E_G^{X_0}$ is not Borel reducible to $E_H$. 

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 In particular $E_G$ and $E_H$ are not {\it orbit equivalent}. 


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\newpage 

\n {\bf Definition} Two equivalence relations $E$ and $F$ on standard Borel probability 
spaces $(X, \mu)$ and $(Y, \nu)$ are said to {\it orbit equivalent} if there is a 
measure preserving bijection 

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\[\theta: X\rightarrow Y\] 

\bigskip 

such that for $\mu$-a.e. $x_1$ we have for all $x_2$ 

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\[x_1 E x_2 \Leftrightarrow \theta(x_1) F \theta(x_2).\] 

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Two actions are {\it orbit inequivalent} if the equivalence relations they 
induce are orbit inequivalent. 

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\newpage 

It is already somewhat non-trivial to find orbit inequivalent 
equivalence relations of the indicated form. 

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\n {\bf Theorem} (Dye; 1950's) 
Any two ergodic, free,  measure preserving actions of $\Z$ on standard Borel 
probability spaces are orbit equivalent. 

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In fact, any two ergodic, free, 
measure preserving 
actions of any two infinite abelian groups on any two standard Borel probability 
spaces are necessarily orbit inequivalent. 

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\newpage 

In the 80's Zimmer used techniques from algebraic groups to obtain infinitely 
many orbit inequivalent ergodic measure preserving actions of distinct groups. 
Around the end of the century Adams and Kechris imported these techniques into the 
study of the Borel reducibility ordering. 




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\n {\bf Theorem} (Adams-Kechris; 1999) There are continuum many countable Borel 
equivalence relations, $(E_r)_{r\in 2^{\aleph_0}}$, such that for $r\neq s$ we have 
$E_r$ not Borel reducible to $E_s$. 


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\newpage

Their examples arise from specific groups acting 
in a measurable manner, and the incomparability of the examples is in a part 
a reflection of the groups being distinct -- that is to say, they have fixed groups 
$(G_r)_{r\in 2^{\aleph_0}}$ for which we can take each $E_r$ to be {\it any} orbit 
equivalence relation induced by a free, ergodic, measure preserving action of 
$G_r$. The examples are non-treeable. 

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The pattern of these results is to suggest that different equivalence relations 
are associated with different groups. 


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Recently attention has turned to finding an analog of the Adams-Kechris examples 
for the treeable equivalence relations. This seems to turn into a problem about 
actions of the free group. 


\newpage 

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\n {\bf Fact} If $E$ is a countable, Borel, treeable equivalence relation on a standard 
Borel probability space $(X, \mu)$ which satisfies certain further mild assumptions 
(e.g. it arises from a free, ergodic, measure preserving action of some group $G$), then there 
is a non-null set 
\[A\subset X\] 
such that 
\[E|_A\] 
is given by a free, ergodic, measure preserving action of either $\Z$ (hence $E\leq_B E_0$ a.e.), or 
\[\F_2\] 
(the free group on two generators), or 
\[\F_\infty\] 
(the free group on $\aleph_0$ many generators). 



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This seems to put us into the situation of needing to find many orbit inequivalent 
actions of the free group, a problem known in ergodic theory which remained open until 
only a couple of months ago: 

\newpage 

\n {\bf Theorem} (Gaboriau-Popa; 2003) There are continuum many non-orbit equivalent 
free, ergodic, measure preserving actions of $\F_2$ on standard Borel probability spaces. 

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Unlike the techniques of Zimmer, their argument appears to give no hint of how it 
might be adapted for $\leq_B$-incomparability. 

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At the present time very little is known about the structure of the treeable 
equivalence relations under $\leq_B$-reducibility. 

\newpage 

Kechris and Louveau established 
that there is a ``universal" treeable equivalence relation 
$E_{\t\infty}$ which is strictly above $E_0$. 


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Then last year it was shown by unrelated 
techniques that there is a third example which is strictly between -- so that we have 
as our sum total of known treeable, countable, Borel equivalence relations 

\[ E_0 <_B E <_B E_{\t\infty}.\] 


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Nothing more is known beyond this. 



\newpage 





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