1. Which of the following is a solution to the differential equation
ylny + xy’ = 0 for x > 0 ?
|
A. xlny = 1 |
B. xylny = 1 |
C. (lny)2 = 2 |
|
D. –y(lny)(lnx) = 1 |
E. lny + (x2/2)y = 1 |
Solution: The answer is A
To solve the differential equation,
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First solve for y’, as follows;
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Notice that this is a first order separable differential equation whose solution is given by separating the variables and their corresponding differentials on each side of the equation and integrating both sides. Hence,
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By substitution, that is, let
, then
and thus, ![]()
Substituting this result in equation (1) and integrating the right side of equation (1) we obtain the following equation:

Where k is a constant. Thus, xlny = 1 is a solution to the differential equation ylny + xy’ = 0 for x > 0.